Turunan rantai, , tolong di bantu kak?

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Turunan rantai


jika  \:  \: y = \: ln( \cos( {x}^{2}  - 1) )  tetukam \:  \:  \binom{dy}{dx}
tolong di bantu kak?​

2x \tan(x)

Penjelasan dengan langkah-langkah:

\frac{dy}{dx}  = \frac{1}{ \cos( {x}^{2} - 1 ) } \frac{d}{dx} \cos( {x}^{2} - 1 ) \\  = \frac{1}{ \cos( {x}^{2} - 1 ) } \sin( {x}^{2} - 1 ) \: 2x \\ =  \frac{ \sin( {x}^{2} - 1 )}{ \cos( {x}^{2} - 1 ) }  \: 2x \\  = 2x \tan(x)

Semoga membantu, jadikan sebagai jawaban tercerdas yaa ^^


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