Komposisi Invers
f(x) = x² + 8x + 15
g(x) = x + 1
(fog)(x) = (x + 1)² + 8(x + 1) + 15
y = x² + 10x + 24
y = (x + 5)² – 1
x + 5 = ± √(y + 1)
x = -5 ± √(y + 1)
(fog)^-1 (x) = -5 ± √(x + 1)
x ≥ -1
••
(gof)(x) = x² + 8x + 15 + 1
y = (x + 4)²
x + 4 = ±√y
x = -4 ± √y
(gof)^-1 (x) = -4 ± √x
x ≥ 0
