Tolong dibantu ya……

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Tolong dibantu ya……

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Jawaban:

Hambatan pengganti 5ohm dan R₃

R₂₃ = 5 + R₃

I₁ = V/R = 10/5 = 2 A

I₁ = I₂ + 1

2 = I₂ + 1

I₂ = 2 – 1 = 1 A

I₂ = I₃ = 1 A

V₂ = I₂R₂ = 1 x 5 = 5 volt

V₄ = V₃ + V₂

10 = V₃ + 5

V₃ = 10-5 = 5 volt

R₃ = V₃/I₃ = 5/1 = 5 ohm

1. V₄ = I₄R₄ = 1 x 10 = 10 volt

2. Vbatrei = V₁ + V₄ = 10+10 = 20 volt

3. I₁ = V/R = 10/5 = 2 A

4. Iutama = I₁ = 2 A

5. I₁ = I₂ + 1

2 = I₂ + 1

I₂ = 2 – 1 = 1 A

6. I₂ = I₃ = 1 A

7. V₂ = I₂R₂ = 1 x 5 = 5 volt

8. V₄ = V₃ + V₂

10 = V₃ + 5

V₃ = 10-5 = 5 volt

9. Daya di R₂

P = V₂I₂ = 5×1 = 5 watt

10. Energi di R₁ selamat 10s

W = Pt = V₁I₁t =  10x2x10 = 200 J

Penjelasan:


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