Jawaban:
Hambatan pengganti 5ohm dan R₃
R₂₃ = 5 + R₃
I₁ = V/R = 10/5 = 2 A
I₁ = I₂ + 1
2 = I₂ + 1
I₂ = 2 – 1 = 1 A
I₂ = I₃ = 1 A
V₂ = I₂R₂ = 1 x 5 = 5 volt
V₄ = V₃ + V₂
10 = V₃ + 5
V₃ = 10-5 = 5 volt
R₃ = V₃/I₃ = 5/1 = 5 ohm
1. V₄ = I₄R₄ = 1 x 10 = 10 volt
2. Vbatrei = V₁ + V₄ = 10+10 = 20 volt
3. I₁ = V/R = 10/5 = 2 A
4. Iutama = I₁ = 2 A
5. I₁ = I₂ + 1
2 = I₂ + 1
I₂ = 2 – 1 = 1 A
6. I₂ = I₃ = 1 A
7. V₂ = I₂R₂ = 1 x 5 = 5 volt
8. V₄ = V₃ + V₂
10 = V₃ + 5
V₃ = 10-5 = 5 volt
9. Daya di R₂
P = V₂I₂ = 5×1 = 5 watt
10. Energi di R₁ selamat 10s
W = Pt = V₁I₁t = 10x2x10 = 200 J
Penjelasan:
