Pada segitiga ABC lancip, dik cos A=4/5 dan sin B=12/13 maka sin C=

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Pada segitiga ABC lancip, dik cos A=4/5 dan sin B=12/13 maka sin C=​

Jawaban:

cos A = 4/5 = sa/mi

de = akar (5² – 4²)

de = akar (25-16)

de= √9 = 3

sin A = de/mi = 3/5

sin B = 12/13 = de/mi

sa = akar (13²- 12²)

sa = akar (169-144)

sa =√25 = 5

cos B = sa/mi = 5/13

A + B + C = 180

C = 180 – (A + B)

sin C = sin 180 – (A + B)

sin C = sin (A + B)

sin C = sin A cos B + cos A sin B

sin C = 3/5. 5/13 + 4/5. 12/13

sin C = 15/65 + 48/65

sin C = 63/65


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