Mr. Cruz a coach of a basketball team,wants to reapaint a certian spot in his basketball court. The picture below shows the area in his court called the key. What is the area of the key that needs repainting given that the radius of the circle is 6ft?
follow the steps discussed in the lesson. Use π = 3.14
What is asked:___________
What are the given:_____________
How are you going to solve the problem?_____________
Translate the problem into a number sentence.__________
what is the area of the key that is needs repainting.
The given are the length of the key and the radius of the circle.
First, find the area of the key. then find the area of the circle. Then subtract the area of the circle from the total area of the key.
area of the key = 15 ft × 6 ft = a
area of the circle = 1/2 ((3.14)(3ft)²)
First, find the area of the key.
a=15ft × 6ft
A= 90 ft²
second, find the area of the circle.
given that it is a semicircle,
thus, A=1/2(3.14× r)²
a=1/2 ( 3.14 x 6ft²)
= 1/2 ( 3.14 x 36ft)
=1/2 ( 113 04ft)
A= 56.52 ft
now subtract the area of the circle from the area of the key;
90 ft – 56.52 ft = 33.48 ft
The area of the key that needs repainting is 33.48ft.