Dimensi Tiga
Balok
AB = 12 cm
BC = 5 cm
AE = 5 cm
BD = √(AB² + AD²) = √(12² + 5²)
BD = 13 cm
X pada BD
AX ⊥ BD
Jarak A ke BD
= AX
= AD × AB / BD
= 5 × 12 / 13
= 4,6 cm
Dimensi Tiga
Balok
AB = 12 cm
BC = 5 cm
AE = 5 cm
BD = √(AB² + AD²) = √(12² + 5²)
BD = 13 cm
X pada BD
AX ⊥ BD
Jarak A ke BD
= AX
= AD × AB / BD
= 5 × 12 / 13
= 4,6 cm