# A solution of an unknown non-dissociating solute was prepared by dissolving, 0.300 g of the substance in 40.0 g of CCl4. The boiling point of the solution was , 0.357 \xb0C higher than that of the pure solvent. Calculate the molar mass of the , solute. Kb=5.02 \xb0C/m

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A solution of an unknown non-dissociating solute was prepared by dissolving

0.300 g of the substance in 40.0 g of CCl4. The boiling point of the solution was

0.357 °C higher than that of the pure solvent. Calculate the molar mass of the

solute. Kb=5.02 °C/m​

### Given:

mass of solute = 0.300 g

mass of solvent = 40.0 g = 0.0400 kg  solute: unknown non-dissociating solute

solvent: CCl₄

### Required:

molar mass of solute

### Solution:

Step 1: Calculate the molality of solution.  molality = 0.0711155 molal

Step 2: Calculate the number of moles of solute.

Note: 1 molal = 1 mol/kg

moles of solute = molality × mass of solvent

moles of solute = 0.0711155 mol/kg × 0.0400 kg

moles of solute = 0.00284462 mol

Step 3: Calculate the molar mass of solute.    #CarryOnLearning